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Question 1:

  • The given diagram shows four processes i.e., isochoric, isobaric, isothermal and adiabatic. The correct assignment of the processes, in the same order is given by

  • A)

    d a c b     \begin{matrix} dacb & & \text{~} & \text{~} \\ \end{matrix}

    B)

    d a b c dabc

    C)

    a d b c adbc

    D)

    a d c b adcb

    Answer:

    Solution:

    In an isochoric process, volume remains constant while in isobaric process, pressure remains the same.

    Slope of an isothermal process is given as P V - \frac{P}{V}

    while for an adiabatic process, slope of P V P - V curve is γ P V - \frac{\gamma P}{V} , where γ > 1 \gamma > 1 .

    \therefore\ Adiabatic curve is steeper than isothermal curve.

    Prev Exam(s):

    JEE MAIN

    - 2019

    , 8 Apr Shift-02

    Chapter:

    THERMODYNAMICS

    Question Level:

    L2

    Tags:

    • THERMODYNAMICS
    • PHYSICS
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